How many solutions does this linear system have y 2x 5?

Solution:

It is given that

y = 2x - 5

2x - y = 5 …. (1)

-8x - 4y = -20

Divide both sides by -4

2x + y = 5 …. (2)

From both the linear equations we know that

a1 = 2

b1 = -1

c1 = 5

a2 = 2

b2 = 1

c2 = 5

Here a2/a1 = b2/b1

Substituting the values

2/2 = 1/-1

1 ≠ -1

Thus on solving the system of linear equations, we get an intersecting line that has a unique solution and it is (5/2,0)

Therefore, the linear system has only one solution.


How many solutions does this linear system have? y = 2x - 5 and -8x - 4y = -20

Summary:

The linear system y = 2x - 5 and -8x - 4y = -20 has only one solution.

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How many solutions does this linear system have? y=2x-5 -8x-4y=-20 one solution: -2.5,0 one solution: 2.5,0 no solution infinite number of solutions

Question

How many solutions does this linear system have y 2x 5?

Gauthmathier5941

Grade 9 · 2021-07-07

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How many solutions does this linear system have? How many solutions does this linear system have? y - Gauthmath -8x-4y=-20
one solution: (-2.5,0)
one solution: (2.5,0)
no solution
infinite number of solutions

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To solve this linear system, we need to find the solutions to the equation y = 2x – 5 –8x – 4y = –20. The first step is to find the equation's roots. To do this, we need to use the quadratic equation solver on our calculator. To find the roots of this equation, we need to input the values for x into the solver, and then press the "roots" button. After finding the roots, we can use these values to solve for y. To do this, we need to use the coefficients from the quadratic equation solver. After solving for y, we can use these values to solve for x. The final step is to combine these two solutions to get our final answer. To do this, we need to use the "combine" button on our calculator, and then input the values into y = 2x – 5 –8x – 4y = –20.

How many solutions does this linear system have 2x 5?

The linear system y = 2x - 5 and -8x - 4y = -20 has only one solution.

Is 2x 5 a linear equation?

It's equivalent to 2x+4y −3 = 0, and 2x + 4y − 3 is a linear polynomial. y = 2x + 5 is a linear equation.

What are the solutions to the system of equations x2 y2 5?

The solutions to the system of equations x2 + y2 = 5 and y = 2x are (1, 2) and (-1, -2).

How do you know how many solutions a linear system has?

A linear equation in two variables is an equation of the form ax + by + c = 0 where a, b, c ∈ R, a, and b ≠ 0. When we consider a system of linear equations, we can find the number of solutions by comparing the coefficients of the variables of the equations.