Consider a^{9}+27b^{12}. Rewrite a^{9}+27b^{12} as \left(a^{3}\right)^{3}+\left(3b^{4}\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right). We think you wrote: Show This solution deals with simplification or other simple results. Step by Step SolutionStep 1 :Equation at the end of step 1 :(0 - (24 • (a15))) + 53b18 Equation at the end of step 2 :(0 - (23•3a15)) + 53b18 Step 3 :Trying to factor as a Difference of Squares :3.1 Factoring: 125b18-24a15 Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) = Note : AB = BA is the commutative property of multiplication. Note : - AB + AB equals zero and is therefore eliminated from the expression. Check : 125 is not a square !! Ruling : Binomial can not be factored as the Trying to factor as a Difference of Cubes:3.2 Factoring: 125b18-24a15 Theory : A difference of two perfect cubes, a3 - b3 can be factored into Proof : (a-b)•(a2+ab+b2) = Check : 125 is the cube of 5 Check : 24 is not a cube !! Final result :125b18 - 24a15 Which expression is a sum of cubes?A polynomial in the form a 3 + b 3 is called a sum of cubes.
Which expression is a difference of cubes?A polynomial in the form a 3 – b 3 is called a difference of cubes.
Which expression is a perfect cube?The perfect cube formula is simply expressed as some integer x to the power or exponent of 3; i.e., x3 which is equal to x⋅x⋅x x ⋅ x ⋅ x . This formula also works with negative numbers because the exponent of 3 is an odd number.
What is the cube root of b27?Therefore, the cube root of 27 by prime factorization is (3 × 3 × 3)1/3 = 3.
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