What is the magnitude between the earth and a 1 kg object on its surface?

Mass of the body, m= 1 kg Mass of the Earth, M= 6 x 10^24 kg Radius of the earth, R= 6.4 x 10^6 m Now magnitude of the gravitational force (F) between the earth and the body can be given as F = GMm/R^2. Putting values we get, F = 9.8 N

Given that, Mass of the body, m = 1 kg Mass of the Earth, M=6×1024kg Radius of the Earth, R=6.4×106mFrom the universal law of gravitation, the magnitude of the gravitational force (F) between the earth and the body is given by, (adsbygoogle = window.adsbygoogle || []).push({}); F=GM×mR2where G=6.67×10−11 Nm2/kg2 is the universal gravitational constant. Hence, magnitude of the gravitational force (F) between the earth and the body is given by, F=GM×mR2=6.67×10−11×6×1024×1(6.4×106)2 = 9.77 N = 9.8 N (approx).

Given:

Mass of the earth is $6\times10^{24}\ kg$ and radius of the earth is $6.4\times 10^6\ m$.

To do:

To find the magnitude of the gravitational force between the earth and a $1\ kg$ object on its surface.


Solution:

We know the formula that is used to calculate the force of gravitation between two objects:

$F=G\frac{Mm}{R^2}$

Here, $F\rightarrow$ Force of gravitation

$M\rightarrow$ Mass of the object 1st

$m\rightarrow$ mass of the object 2nd

$R\rightarrow$ distance between the two objects

Let us calculate the magnitude of the gravitational force between the earth and a $1\ kg$ object on its surface by using the above formula:

Calculation of gravitational force:

Here given, the mass of the body $m=1\ kg$

Mass of the earth $M=6\times10^{24}\ kg$

Radius of earth $R=6.4\times10^{6}\ m$

Gravitational constant $G=6.7\times10^{-11}\ Nm^2kg^{-2}$

Therefore, the force of gravity on the body $F=G\frac{Mm}{R^2}$

Or $F=6.7\times10^{-11}\times\frac{(6\times10^{24})\times1}{(6.4\times10^{6})^2}$

Or $F=9.82\ N$

Therefore, the force of gravity on a body of mass $1\ kg$ lying on the surface of the earth is $9.82\ N$.

What is the magnitude between earth and 1 kg object?

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1 0 24 10^{24} 1024 kg and radius of the earth is 6.4 × 1 0 6 10^6 106 m). This shows that Earth exerts a force of 9.8 N on a body of mass 1 kg.

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface Mass of the earth is 6/10 24 kg and radius of the earth is 6.4 106m?

Hence, magnitude of the gravitational force (F) between the earth and the body is given by, F=GM×mR2=6.67×10−11×6×1024×1(6.4×106)2 = 9.77 N = 9.8 N (approx).