What happens to red blood cells placed in 5% NaCl solution?

Blood Laboratory

Red cell fragility > Osmotic hemolysis
  Cell membranes are semipermeable barriers, and osmotic gradients are established between intracellular and extracellular fluids which can cause water to flow into and out of the cells. The amount of osmotic pressure depends upon the difference between the concentration of non-diffusible ions on each side of the membrane.
The theoretical background for this exercise is to be reviewed in your text book.
The intracellular fluid of erythrocytes is a solution of salts, glucose, protein and hemoglobin. A 0.9% NaCl solution is said to be isotonic: when blood cells reside in such a medium, the intracellular and extracellular fluids are in osmotic equilibrium across the cell membrane, and there is no net influx or efflux of water.

When subjected to hypertonic media (e.g. 1.8% NaCl), the cells lose their normal biconcave shape, undergoing collapse (leading to crenation) due to the rapid osmotic efflux of water.

On the other hand, in a hypotonic environment (e.g. 0.4% NaCl or distilled water), an influx of water occurs: the cells swell, the integrity of their membranes is disrupted, allowing the escape of their hemoglobin (hemolysis) which dissolves in the external medium.

What happens to red blood cells placed in 5% NaCl solution?
Crenation

What happens to red blood cells placed in 5% NaCl solution?
Hemolysis

In this experiment, we make use of the property that the osmotic fragility (or susceptibility to hemolysis) of erythrocytes is not uniform, and the number of cells undergoing hemolysis depends on the degree of hypotonicity of the extracellular medium. The concentration of liberated hemoglobin in each test medium is an index of the extent of osmotic hemolysis. Your task is to examine the relationship between extent of hemolysis and osmolarity of the medium in which the erythrocytes are suspended.

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The cell will swell up and burst.

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The cell will stay the same size.

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The cell will shrink as it loses water to the salt solution.

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The cell will resist osmosis due to its non permeable membrane.

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Solution

The correct option is C The cell will shrink as it loses water to the salt solution.The intracellular concentration of the RBC is more dilute or hypotonic compared to the salt solution. Hence, the salt solution acts as a hypertonic solution when compared to the RBC. Therefore, water will move out of the RBC by osmosis and will result in the shrinking of the RBC (water moves from a hypotonic solution to a hypertonic solution).

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What would happen to the red blood cells after exposure to the 5% NaCl solution?

The red blood cells, therefore, lose their normal biconcave shape and shrink or crenate.

Why is a 5% NaCl solution hypertonic to red blood cells?

The red blood cells in the 5% NaCl was present in an hypertonic solution, so the water rushed out of the red blood cells due to osmosis. There was a higher concentration of solutes in the extracellular fluid (NaCl) than the intracellular fluid.

What happens when you put red blood cells in NaCl?

The bursting of the red blood cell is called hemolysis. If a red blood cell is placed in a solution that contains 0.85% NaCl the water moves equally out and into the cell, the solution in the cell and the solution around the cell are the same or in equilibrium. There is no net gain or loss of water from the cell.

What would happen to a person's red blood cells if a solution containing 5% salt instead of the isotonic 0.9% salt were given intravenously?

The red blood cell would shrink as it loses water to the salt solution in the test tube.