How to calculate the freezing point of an aqueous solution

How to calculate the freezing point of an aqueous solution
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Key Concepts

Boiling Point Elevation:

  • A liquid boils at the temperature at which its vapor pressure equals atmospheric pressure.
  • The presence of a solute lowers the vapor pressure of the solution at each temperature, making it necessary to heat the solution to a higher temperature to boil the solution.
  • In dilute solutions with a nonvolatile solute, the boiling point elevation is proportional to the molality of the solute particles:
    ΔTb = Kbm
        ΔTb = the amount by which the boiling point is raised
        m = molality (moles solute particles per kg of solution)
        Kb = molal boiling-point elevation constant (solvent dependent)
  • Boiling Point of solution = normal boiling point of solvent + ΔTb

Freezing Point Depression:

  • A solute lowers the freezing point of a solvent.
  • In dilute solutions, the freezing point depression is proportional to the molality of the solute particles:
    ΔTf = -Kfm
        ΔTf = the amount by which the freezing point is lowered
        m = molality (moles solute particles per kg of solution)
        Kf = molal freezing-point depression constant (solvent dependent)
  • Freezing Point of solution = normal freezing point of solvent + ΔTf

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Some Boiling-Point Elevation and Freezing-Point Depression Constants

solventnormal boiling
point (oC)
Kb (oCm-1)normal freezing
point (oC)
Kf (oCm-1)
benzene 80.2 2.53 5.5 5.12

water 100.0 0.512 0.000 1.855

acetic acid
(ethanoic acid)
118.5 3.07 16.6 3.90

camphor 208.3 5.95 178.4 40.0

naphthalene 218.0 5.65 80.2 6.9

Example: Calculating Boiling and Freezing Point of a Nonelectrolyte Solution

For a 0.262 m solution of sucrose in water, calculate the freezing point and the boiling point of the solution.

Freezing Point CalculationBoiling Point Calculation
  1. Calculate the freezing point depression:
    ΔTf = -Kfm
    Kf = 1.855 (from table above)
    m = 0.262 m
    ΔTf = -1.855 × 0.262 = -0.486oC
  2. Calculate the freezing point of the solution:
    Tf (solution) = normal freezing point + ΔTf
    Tf (solution) = 0.000 - 0.486 = -0.486oC
  1. Calculate the boiling point elevation:
    ΔTb = Kbm
    Kb = 0.512 (from table above)
    m = 0.262 m
    ΔTb = 0.512 × 0.262 = 0.134oC
  2. Calculate the boiling point of the solution:
    Tb (solution) = normal boiling point + ΔTb
    Tb (solution) = 100.00 + 0.134 = 100.134oC

Example: Calculating Boiling and Freezing Point of an Electrolyte Solution

Calculate the freezing point and boiling point for a 0.15 m aqueous solution of sodium chloride.

Freezing Point CalculationBoiling Point Calculation
  1. Calculate the freezing point depression:
    ΔTf = -Kfm
    Kf = 1.855 (from table above)
    Since: NaCl → Na+(aq) + Cl-(aq):
    m(Na+) = 0.15 m
    m(Cl-) = 0.15 m
    m(NaCl(aq)) = 0.15 + 0.15 = 0.30 m
    ΔTf = -1.855 × 0.30 = -0.557oC
  2. Calculate the freezing point of the solution:
    Tf (solution) = normal freezing point + ΔTf
    Tf (solution) = 0.000 - 0.557 = -0.557oC
  1. Calculate the boiling point elevation:
    ΔTb = Kbm
    Kb = 0.512 (from table above)
    Since: NaCl → Na+(aq) + Cl-(aq):
    m(Na+) = 0.15 m
    m(Cl-) = 0.15 m
    m(NaCl(aq)) = 0.15 + 0.15 = 0.30 m
    ΔTb = 0.512 × 0.30 = 0.154oC
  2. Calculate the boiling point of the solution:
    Tb (solution) = normal boiling point + ΔTb
    Tb (solution) = 100.00 + 0.154 = 100.154oC

Example: Calculating Molar Mass of Solute

Boiling Point Elevation Problem:
1.15 g of an unknown, nonvolatile compound raises the boiling point of 75.0 g benzene (C6H6) by 0.275oC.
Calculate the molar mass of the unknown compound.

Boiling Point Elevation Problem Solution:

  1. Calculate the molality of solute particles:
    m = ΔTb ÷ Kb
        ΔTb = 0.275oC
        Kb = 2.53oCm-1 (from table above)
    m = 0.275 ÷ 2.53 = 0.109 m
  2. Calculate the moles of solute present:
    molality = moles solute ÷ kg solvent
    moles(solute) = m × kg solvent = 0.109 × 75.0 × 10-3 = 8.175 × 10-3 mol
  3. Calculate the molar mass of the solute:
    moles(solute) = mass(solute) ÷ molar mass(solute)
    molar mass(solute) = mass(solute) ÷ moles(solute) = 1.15 ÷ 8.175 × 10-3 = 141 g mol-1

How do you find the freezing point of aqueous solution?

Example: Calculating Boiling and Freezing Point of a Nonelectrolyte Solution.
Calculate the freezing point depression: ΔTf = -Kfm. Kf = 1.855 (from table above) m = 0.262 m. ... .
Calculate the freezing point of the solution: Tf (solution) = normal freezing point + ΔTf Tf (solution) = 0.000 - 0.486 = -0.486oC..

How do you determine freezing point?

To calculate the freezing point of an electrolytic solution, we can use the same formula ∆Tf = Kf m that is used to calculate the freezing point using molality. But before using the formula, we have to analyze the number of ions and calculate its molality.

What is the freezing point of 1% na2so4 solution?

Thus, the freezing point of aqueous solution of sodium sulphate is Tf=−0.8742 ∘C T f = − 0.8742 ∘ C .

What is the freezing point of an aqueous 1 m?

The freezing point of a 1.00 m aqueous solution of HF is found to be – 1.91°C. The freezing point constant of water, Kris 1.86 K kg mol-!.