For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants. 4al(s) 3o2(g)â????2al2o3(s)

4Al(s)+3O2 (g)-->2Al2O3 (s)

4 mol Al
2.6 mol O2

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1 answer

1. The equation tells you that 4 mol Al will require 3 mol O2. You have only 2.6 mol O2; therefore, O2 must be the limiting reagent.

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