What the date today in numbers

What is today’s date?

Find out the current day, date of today, local time and week number.

NEW! Try our days from today calculator…

The correct way of writing today’s date?

There are two ways to write a date:

1. using entirely numbers and
2. using a combination of words and numbers.

Then there are also two standards for writing today’s date:

• the American English standard
  (month-day-year)
• the British English standard
  (day-month-year)

Writing the date including weekday

The weekday always comes first and is separated from the rest by a comma:

• Weekday, Month Date (date in digits), 2019 (American)
• Weekday, Date (date in digits) Month 2019 (British)
  ( Please note there is no comma between the date and the year. )

Different standards can cause confusion

If you write the date with only digits it can easily lead to misunderstanding.
For example the date 10/03/2020 can be either:

1. October 3, 2020 (American interpretation)
2. March 10 2020 (British interpretation)

This is a reason why it can be better to write the name of the month.

Abbrevations for day of the Week

1. Sunday – Sun.
2. Monday – Mon.
3. Tuesday – Tue. or Tues.
4. Wednesday – Wed.
5. Thursday – Thu.
6. Friday – Fri.
7. Saturday – Sat.

Abbrevations for Months

1. January – Jan.
2. February – Feb.
3. March – Mar.
4. April – Apr.
5. May – May
6. June – Jun.
7. July – Jul.
8. August – Aug.
9. September – Sep.
10. October – Oct.
11. November – Nov.
12. December – Dec.

Today’s date in numbers and slashes

When writing the date by numbers only, you can separate them by using
a hyphen (-), a slash (/), or a dot (.)

You can write the date with or without leading zeros. For example:

• 10/03/2020 or 10/3/2020

Today Tuesday, September 20, 2022 is ...

Day 263

Day of the year is a number between 1 and 365 (in 2022), January 1 is day 1.
After today 102 days are remaining in this year.

This page uses the ISO-8601 ordinal date format.

There is also another less-used format: the 'ISO day of year' numbers, this is a number between 1 and 371, day 1 of the year is Monday of the first ISO week (where the first Thursday of the new year is in week 1).

Lists of day numbers by year: 2021 - 2022 - 2023 - 2024 ...

Programming routines

Microsoft Excel

Calculate today's day-number, starting from the day before Jan 1, so that Jan 1 is day 1.

=TODAY()-DATE(YEAR(TODAY()),1,0) or, for any date entered in cell A1, calculate the corresponding day-number in that date’s year: =A1-DATE(YEAR(A1),1,0)

Google Docs Spreadsheet

=DATEDIF(CONCAT("1-1-";year(now()));today();"D")+1

Calculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber. (Your date format (1-1-year) may be different)

LibreOffice Calc:

=ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1

PHP

$dayNumber = date("z") + 1;

You can use an epoch to find other day numbers:

date("z", epoch) + 1

date("z") starts counting from 0 (0 through 365)!

Python

from datetime import datetime day_of_year = datetime.now().timetuple().tm_yday

PERL

use Time::Piece; my $day_of_year = localtime->yday + 1; # ... or ... my $day_of_year = (localtime)[7] +1; # ... or (if you really want to use POSIX) ... use POSIX; my $day_of_year = POSIX::strftime("%j", time);

Replace time with other epochs for other days.

MySQL

SELECT DAYOFYEAR(NOW())

Day number between 1 and 366. Replace now() with other dates eg.:

SELECT DAYOFYEAR('2022-02-20');

Oracle

select to_char(sysdate, 'DDD') from dual select to_char(to_date('2022-02-20','YYYY-MM-DD'), 'DDD') from dual

Delphi

using DateUtils, SysUtils; DayOfTheYear(Date);

Microsoft Access

DatePart("y", Now())

Visual Basic (VB.NET)

Dim dayOfYear As Integer = DateTime.Now.DayOfYear

JavaScript

var today = new Date(); Math.ceil((today - new Date(today.getFullYear(),0,1)) / 86400000);

Or add a 'Day of Year' method to the date object:

Date.prototype.getDOY = function() { var onejan = new Date(this.getFullYear(),0,1); return Math.ceil((this - onejan) / 86400000); } var today = new Date(); var daynum = today.getDOY();

Java

LocalDate.now().getDayOfYear();

Unix/Linux

date +%j

ColdFusion

#dayofyear(now())#

Objective C

int currentDay; dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setDateFormat:@"D"]; date = [NSDate date]; currentDay = [[dateFormatter stringFromDate:date] intValue];

C++

Read the comment below by Mmars.

C#

int iDayOfYear = System.DateTime.UtcNow.DayOfYear;

R

format(Sys.Date(), "%j")

Ruby

time = Time.new puts time.yday

Powershell

$DayOfYear = (Get-Date).DayofYear Write-Host $DayOfYear

LiveCode

on mouseUp put "January 1," && the last word of the long date into firstDayofYear --append current year convert firstDayofYear to seconds -- from Jan 1, 1970 to first day of this year put the long date into currentDay convert currentDay to seconds -- from Jan 1, 1970 GMT to today put currentDay - firstDayofYear into totalSeconds answer the round of (totalSeconds / (60*60*24)) + 1 --display total days in dialog box end mouseUp

Or:

on mouseUp answer DayOfYear() end mouseUp function DayOfYear put the short date into currentDate convert currentDate to dateItems --list of date elements separated by commas put item 1 of currentDate into year put item 2 of currentDate into month put item 3 of currentDate into day put floor (275 * month / 9) into N1 put floor ( (month + 9) / 12) into N2 put (1 + floor ( (year - 4 * floor (year / 4) + 2) / 3) ) into N3 put N1 - (N2 * N3) + day - 30 into N return N end DayOfYear function floor pNumber -- LiveCode has no built-in floor() function put Round (pNumber) into theInteger if theInteger > pNumber then put theInteger - 1 into theInteger end if return theInteger end floor

T-SQL (Transact-SQL)

SELECT DATEPART(DAYOFYEAR, SYSDATETIME())

or

SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '-01-01',getdate()+1) AS number_of_today

Go (golang)

day := time.Now().YearDay()

Matlab

dayNumber = today-datenum(['1-Jan-' year(today)])+1

Powerbuilder

Read the comment below by Danny Cruz.

 
Thanks to all the developers who contributed to this page! (read comments below)

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