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Question 319019: Find an equation
of the line that passes through the point (-1,3) and is parallel to the line passing through the points (-2,-3) and (2,5). Answer by Fombitz(32382) (Show Source): You can put this solution on YOUR
website! First find the line. The formula for the slope of a line is, Parallel lines have identical slopes.
Use the point (-1,3) to solve for b.
. . . Parallel Line . . .
. . . I inadvertently solved for the perpendicular line first and then realized that you were looking for a parallel line. Here's how to do
it if you're looking for a line perpendicular to your original line that goes through (-1,3). . . . Perpendicular lines have slopes that are negative reciprocals,
The slope of the second line is Use the point
(-1,3) to solve for b. .
. . Perpendicular Line . . .
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Solution
The correct option is A
y+2=0,3
x-y-2-33=0
Calculate the equations:
The given equation of line is 3x+y=1⇒y=-3x+1
This is of the form y=mx+c
Slope of the line is -3.
Let m be the slope of other line which make 60° with the given line.
We know tanθ=m
2-m11+m1m2
tan60°=-3-m
1-3m3=-3-m1-3m
3-3m=-3-mor3-3m=3+m⇒m=3or
m=0
The line passes through 3,-2.
Required equation is y-y1=mx-x1
⇒y+2=3x-3&y+2=0⇒3x-y-2-3
3=0&y+2=0
Hence y+2=0,3x-y-2-33=0 are
the required equations and therefore option A is the answer.
Solve
Textbooks
Question Papers
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