Solution:
It is given that
y = 2x - 5
2x - y = 5 …. (1)
-8x - 4y = -20
Divide both sides by -4
2x + y = 5 …. (2)
From both the linear equations we know that
a1 = 2
b1 = -1
c1 = 5
a2 = 2
b2 = 1
c2 = 5
Here a2/a1 = b2/b1
Substituting the values
2/2 = 1/-1
1 ≠ -1
Thus on solving the system of linear equations, we get an intersecting line that has a unique solution and it is (5/2,0)
Therefore, the linear system has only one solution.
How many solutions does this linear system have? y = 2x - 5 and -8x - 4y = -20
Summary:
The linear system y = 2x - 5 and -8x - 4y = -20 has only one solution.
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How many solutions does this linear system have? y=2x-5 -8x-4y=-20 one solution: -2.5,0 one solution: 2.5,0 no solution infinite number of solutions
Question
Gauthmathier5941
Grade 9 · 2021-07-07
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How many solutions does this linear system have?
How many solutions does this linear system have? y - Gauthmath
-8x-4y=-20
one solution:
(-2.5,0)
one solution:
(2.5,0)
no solution
infinite number of solutions
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To solve this linear system, we need to find the solutions to the equation y = 2x – 5 –8x – 4y = –20. The first step is to find the equation's roots. To do this, we need to use the quadratic equation solver on our calculator. To find the roots of this equation, we need to input the values for x into the solver, and then press the "roots" button. After finding the roots, we can use these values to solve for y. To do this, we need to use the coefficients from the quadratic equation solver. After solving for y, we can use these values to solve for x. The final step is to combine these two solutions to get our final answer. To do this, we need to use the "combine" button on our calculator, and then input the values into y = 2x – 5 –8x – 4y = –20.