1 decade has 315,360,000 seconds.
That is, if we go by the typical per-year total, which is 31,536,000 seconds.
However, if we want to be more accurate, we have to take into leap years.
There are 2 or 3 leap years per decade. In the 2020s, for example, there are 3 leap years (2020, 2024, 2028). In the 2030, there will be only 2 (2032, 2036). And back to 3 leap years in the 2040s, and so on.
If it’s leap year, then 1 year has 31,622,400 seconds.
Seconds in a decade calculation
Two leap year decades
That means in decades with 2 leap years, we have the following math:
= 8 normal years (seconds) + 2 leap years (seconds)
= 8 * 31,536,000 + 2 * 31,622,400
= 315,532,800
We note that it’s close, but not exact, to our number mentioned at the top. (It’s 0.05% greater.)
Three leap year decades
In decades with 3 leap years, we have the following math:
= 7 normal years (seconds) + 3 leap years (seconds)
= 7 * 31,536,000 + 3 * 31,622,400
= 315,619,200
That’s 0.08% greater than the figure cited at the beginning of this article.
How do we know the number of seconds in a year?
But let’s also back up for a second because we simply told you the number of seconds in a year.
Let’s go through step-by-step how we got there:
– We know that 1 year has 365 days (366 days during leap year).
– We know that 1 day is 24 hours.
– 1 hour is 60 minutes.
– And we know that 1 minute is 60 seconds.
So if we multiply all that through, we have:
= 365 days per year x 24 hours per day x 60 minutes per hour x 60 seconds per minute
= 31,536,000 seconds per year
Of course, now that you know that there are 86,400 seconds per day, you can calculate how many seconds there are…
– per week
– per month
– per year (above)
– per century…
…and virtually every other expanse of time.
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This morning I see an error in my previous calculations! If Year 1 is a leap year, so will Years 5 and 9, giving a total of THREE in the decade, not the two managed to count yesterday! The decade will have either two or three leap years, giving a total of 315,532,800 or 315,619,200 seconds.
This calculation also ignores the thorny issue of exactly how long a day is - depending on whether you use sidereal days or solar days. When you measure in seconds, over 10 years, there is a significant difference.
"A day of exactly 86,400 SI seconds is the astronomical unit of time (the second is not preferred in astronomy).
For a given planet, there are two types of day defined in astronomy:
* sidereal day - a single rotation of a planet with respect to the distant stars
* mean solar day - average time of a single rotation of a planet with respect to its star.
For Earth, the sidereal day is about 3 minutes 56 seconds shorter than the solar day. In fact, the Earth spins 366 times about its axis during a 365-day year, because the Earth's revolution about the Sun removes one apparent turn of the Sun about the Earth."
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Best Answer
#1
Hi thumb, :)
There are 5 steps to answering this:
Step 1) How many seconds are in an hour? You know there's 60 seconds in a minute, and 60 minutes in a hour.
$${\mathtt{60}}{\mathtt{\,\times\,}}{\mathtt{60}} = {\mathtt{3\,600}}$$
Step 2) Find out how many in a day. There's 24hr in a day.
$${\mathtt{3\,600}}{\mathtt{\,\times\,}}{\mathtt{24}} = {\mathtt{86\,400}}$$
Step 3) So that's how many in a day, now there's 365 days in a year.
$${\mathtt{86\,400}}{\mathtt{\,\times\,}}{\mathtt{365}} = {\mathtt{31\,536\,000}}$$
Step 4) There's 10 years in a decade
$${\mathtt{31\,536\,000}}{\mathtt{\,\times\,}}{\mathtt{10}} = {\mathtt{315\,360\,000}}$$
Step 5 ) That's your answer 315360000 seconds.
-MathsGod1
#1
Best Answer
Hi thumb, :)
There are 5 steps to answering this:
Step 1) How many seconds are in an hour? You know there's 60 seconds in a minute, and 60 minutes in a hour.
$${\mathtt{60}}{\mathtt{\,\times\,}}{\mathtt{60}} = {\mathtt{3\,600}}$$
Step 2) Find out how many in a day. There's 24hr in a day.
$${\mathtt{3\,600}}{\mathtt{\,\times\,}}{\mathtt{24}} = {\mathtt{86\,400}}$$
Step 3) So that's how many in a day, now there's 365 days in a year.
$${\mathtt{86\,400}}{\mathtt{\,\times\,}}{\mathtt{365}} = {\mathtt{31\,536\,000}}$$
Step 4) There's 10 years in a decade
$${\mathtt{31\,536\,000}}{\mathtt{\,\times\,}}{\mathtt{10}} = {\mathtt{315\,360\,000}}$$
Step 5 ) That's your answer 315360000 seconds.
-MathsGod1
#2
Thnx man.
well explained.
#4
Very, very nice MG1.......!!!!!
A BIG 3 points from me.....
#6
Thumbs up from me too MG :)